Give the major product of the following react | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is a Friedel-Crafts acylation of $N$-phenylbenzamide (benzanilide) with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$. In

Vedclass · Accepted Answer

Vedclass · Answer

(C) The reaction is a Friedel-Crafts acylation of $N$-phenylbenzamide (benzanilide) with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$. In $N$-phenylbenzamide,the nitrogen atom is attached to two phenyl rings: one from the aniline part and one from the benzoyl part. The $-NHCO-$ group is an ortho/para-directing group because of the lone pair on the nitrogen atom,which increases the electron density on the aniline ring. However,the benzoyl group attached to the nitrogen is strongly electron-withdrawing,which deactivates the benzoyl ring towards electrophilic substitution. Therefore,the electrophilic substitution (Friedel-Crafts acylation) occurs on the more electron-rich aniline ring at the para position due to steric hindrance at the ortho position. Thus,the major product is $N-(4-acetylphenyl)benzamide$.

Give the major product of the following reaction $.$

Similar Questions

Isoniazid is used in the treatment of tuberculosis. Identify the least basic $N$ atom present in it.

Consider the following:
$(I)$ $CH_3CH_2NH_2$
$(II)$ $PhCH_2NH_2$
$(III)$ $PhNH_2$
The correct order of their basic strength is:

The given reaction is $2$-methylbutanamide reacting with $KOBr$ and $\Delta$. What is the correct statement about the product?

Benzylamine is a stronger base than aniline because

The major product in the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module